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16=-2.7x^2+40x+6.5
We move all terms to the left:
16-(-2.7x^2+40x+6.5)=0
We get rid of parentheses
2.7x^2-40x-6.5+16=0
We add all the numbers together, and all the variables
2.7x^2-40x+9.5=0
a = 2.7; b = -40; c = +9.5;
Δ = b2-4ac
Δ = -402-4·2.7·9.5
Δ = 1497.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-\sqrt{1497.4}}{2*2.7}=\frac{40-\sqrt{1497.4}}{5.4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+\sqrt{1497.4}}{2*2.7}=\frac{40+\sqrt{1497.4}}{5.4} $
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